Glasses for nearsightedness and door peepholes

Do Now: Look through the peephole in a door and the whole hallway appears, small and upright. What kind of lens is in the peephole?
A diverging lens. Like a convex mirror, it spreads light out and gives a wide, smaller, upright view.
Travels parallel to the principal axis, then bends away as if it came from F on the near side (trace it back with a dashed line).
Aims toward F on the far side, then leaves the lens parallel.
Goes through the center of the lens without bending.
Object far from the lens — click Next to draw it step by step.
Object close to the lens — click Next to draw it step by step.
Describe the image using L-O-S-T.
L: same side as the object, between F and the lens O: upright S: smaller T: Virtual
A diverging lens behaves just like a convex mirror. The only difference: the lens’s virtual image is on the same side as the object, while the mirror’s is behind the mirror.
Drag the orange object. Turn rays on and off with the check boxes.
Glasses for nearsightedness: the eye focuses light too soon. A diverging lens spreads the light a little so it focuses on the retina.
Door peepholes: a wide, upright view of the hallway.
Telescopes & binoculars: some designs use a diverging eyepiece.
Laser beam expanders: spread a narrow beam before it is re-focused.
5 quick questions — pick an answer to see if you’re right.
1. A diverging lens is
2. A diverging lens always makes an image that is
3. A ray parallel to the principal axis passes through a diverging lens. It leaves the lens
4. Which vision problem is corrected with diverging lenses?
5. Which mirror forms images like a diverging lens does?
A nearsighted person’s eye focuses light from distant objects in front of the retina, so distant objects look blurry. An eye doctor prescribes eyeglasses with diverging lenses.
How does a diverging lens help a nearsighted eye?
Challenge score: 0 / 6
C1. What kind of image does a single diverging lens always form of a real object?
C2. A diverging lens has a focal length of −15 cm (the negative sign shows a virtual focal point). A 6.0-cm-tall object is placed 30. cm from the lens. Substitute numerical values into a mathematical representation that can be used to determine the image distance. Then calculate it.
C3. A student makes the following claim.
Place a check mark in either the Support or Refute box. Justify your response.
C4. For the 6.0-cm-tall object 30. cm from the diverging lens, the image forms 10. cm from the lens on the object’s side. Determine the height of the image.
C5. A ray parallel to the axis passes through a diverging lens. Where does it go?
C6. A hiker tries to start a campfire by focusing sunlight with the lens from a nearsighted friend’s glasses. Predict whether this will work, and explain your prediction.