Do Now warm-up prompt

Angle ≠ 90° — when concurrent forces don't meet at a right angle, the resultant can't be found with the Pythagorean theorem. It must be found graphically.

Ranking Task

Rank the resultants from smallest to largest

Ranking task diagram of several force-vector pairs

Jan 2006

Flash

F. Resultants When the Angle Between Forces ≠ 90°

Given

5 N North & 3 N 30° S of E act concurrently (on a single point).
Find the resultant & equilibrant.

Angle not 90 degrees, can't use Pythagorean theorem

Graphical Method

1. Draw vectors to scale

Two force vectors drawn to scale

2. Make parallelogram

Parallelogram constructed from the two vectors

3. Draw diagonal (resultant)

Diagonal of the parallelogram drawn as the resultant

4. Find magnitude & direction of vector

Graphical Method

1. Measure length, convert to Newtons using scale 1 cm = 1 N

2. Measure angle vector makes with horizontal

↓

Resultant

R = 4.5 N 53° N of E

Equilibrant

E = 4.5 N 53° S of W

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St. Mary's U. Astronomy and Physics Dept.

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Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. Why can't the Pythagorean theorem find the resultant of two forces at 30° to each other?

2. In the parallelogram method, after drawing both vectors to scale from one point, the resultant is

3. Using a scale of 1 cm = 1 N, a resultant drawn with the graphical method measures 4.5 cm. What is its magnitude?

4. A resultant is 4.5 N, 53° N of E. What is the equilibrant?

5. Forces of 5 N and 3 N act on a point at an angle other than 0°, 90° or 180°. Which resultant is possible?