Do Now warm-up prompt

Do Now: On a sunny day at the beach, the sand burns your feet but the ocean water feels cool. They both got the same sunlight. Why?

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Water has a much higher specific heat than sand. It takes far more energy to raise water’s temperature, so the same sunlight warms the sand much more.

A. Specific Heat

Specific heat (c) is the energy needed to raise the temperature of 1 gram of a substance by 1 °C.

SubstanceSpecific Heat, c (J/g•°C)
Water (liquid)4.18
Aluminum0.90
Iron0.45
Copper0.39
Bar chart of temperature change for the same energy added to water, aluminum, iron, and copper
Pattern

High specific heat → temperature changes slowly (water). Low specific heat → temperature changes quickly (metals).

B. The Heat Equation

Q = mcΔT

Heat Equation

Q = heat added or removed (J)

m = mass (g)

c = specific heat (J/g•°C)

ΔT = change in temperature = Tfinal − Tinitial (°C)

If Q comes out negative, the object lost energy (it cooled down).

C. Worked Examples

Example 1

How much heat is needed to warm 250 g of water from 20. °C to 80. °C?

Given: m = 250 g,  c = 4.18 J/g•°C,  ΔT = 80. − 20. = 60. °C

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Q = mcΔT = (250 g)(4.18 J/g•°C)(60. °C)

Q = 62,700 J  (about 63 kJ)

Example 2

A 500-g iron pan absorbs 9,000 J of heat. How much does its temperature rise?

Given: m = 500 g,  c = 0.45 J/g•°C,  Q = 9,000 J

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ΔT = Qmc = 9,000 J(500 g)(0.45 J/g•°C)

ΔT = 40. °C

Example 3

A 200-g sample of an unknown metal absorbs 1,800 J and its temperature rises 10. °C. What is the metal?

Given: m = 200 g,  Q = 1,800 J,  ΔT = 10. °C

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c = QmΔT = 1,800 J(200 g)(10. °C) = 0.90 J/g•°C

From the table, the metal is aluminum.

D. Practice

Problem 1

How much heat does 100. g of water give off as it cools from 90. °C to 30. °C?

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Q = (100.)(4.18)(−60.) = −25,080 J — about 25 kJ released.

Problem 2

A 50.-g piece of copper gains 975 J. How much does its temperature rise?

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ΔT = 975 / (50. × 0.39) = 50. °C

Problem 3

How much energy does it take to heat 2.0 kg (2,000 g) of water from 15 °C to 100. °C for pasta?

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Q = (2,000)(4.18)(85) = 710,600 J ≈ 711 kJ

Problem 4

A 300.-g metal block absorbs 2,700 J while warming by 20. °C. Identify the metal.

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c = 2,700 / (300. × 20.) = 0.45 J/g•°C → iron

E. Specific Heat in the Real World

Coastal climates: oceans warm and cool slowly, so cities near the coast have milder temperatures.

Car radiators: water carries away lots of engine heat with only a small temperature rise.

Cookware: metal pots have low specific heat, so they heat up quickly.

Your body: mostly water, which helps keep your temperature steady.

Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. The same amount of heat is added to 100 g of water and 100 g of iron. Which has the larger temperature increase?

2. How much heat raises 10. g of water by 5.0 °C?

3. Why does the ocean stay cooler than the sand on a sunny day?

4. A 100.-g metal absorbs 390 J and warms by 10. °C. Its specific heat is

5. If Q is negative in Q = mcΔT, the object