AP Physics B
C. Solving Word Problems
ex) A car produces a 92 m skid mark with a deceleration of 7.00 m/s2. What speed was the car travelling just before it applied the brakes?
Vf2 = Vi2 + 2aΔd 0 = Vi2 + 2(-7.00 m/s2)92 m
Vi2 = 1288
Δd = 36 m/s
ex) A car accelerates uniformly from rest at a rate of +10 m/s2. How far will the car travel in 4 seconds?
• Step 2 - Turn all your information into letters
• Step 3 - Substitute and Solve Equation:
Δd = Vit + 1/2aΔt2
= 0 m/s(4 sec)+1/2(10 m/s2)(4s)2
Δd = 0 + 5(16)
Δd = 80 m
Ex) If a car traveling 20 mph can stop in about 40 ft. If the same car was traveling twice as fast, how far would it take to stop?
Vf2 = Vi2 + 2aΔd
0= Vi2 + 2aΔd
-Vi2 = 2aΔd
4 times further
160 ft
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