Friction Relationships

Ranking Task

Rank the friction on the 1.0 kg from greatest to least

rampfriction
Friction graphics

Friction - Fill In The Blanks

Phonebook Friction
- Mythbusters

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Download the file below.

Mythbusters_-_Phone_Book_Friction

Friction Problems

*Remember
Fn = Weight = mg
on horizontal surface

Ex) A 5.0 kg Steel block is resting on a *horizontal table*. The coefficient of static friction (us) is 0.75 and the uk is 0.57.

a) What minimum force is needed to start this block moving (fs)?

fs = Fnus = Fgus = mgus

= 5.0 kg(9.8 m/s2)(.75)

= 37. N

b) What is the frictional force on this object as it moves?

fk = mguk

= 5.0 kg(9.8 m/s2)(.57)

= 28 N

c) What force must be applied to the object to keep it moving at constant velocity? (Hint: Fnet = 0)

At Constant velocity

F applied = friction force

= 28 N

Friction Questions

Coefficients of Friction & F = ma

Remember ...

Static Friction    fs = UsFn

Kinetic Friction  fk = UkFn

On Horizontal Surface

fs = usFg   (force to start object moving)

fk = ukW    AND    W = mg

Example 1

A 1000. N car skids on a wet concrete road. If the road is horizontal, what is the friction force on the car?

w = 1000. N     Uk = .58     fk = ?

Uktable

fk = UkFg = .58 x 1000. N

= 5.8 x 102 N

Example 2

A skier is being pulled along a horizontal surface at constant speed with a force of 50. N. What is the weight of the skier?

At constant speed:
fk = Applied Force

fk = 50. N     w = ?

Uktable

uk = .05

fk = ukFg

50. N = .05[Fg]

w = 1000 N

Example 3

A 10. kg block of wood sliding on a horizontal wooden table is brought to rest. What is the force on the block of wood that caused it to stop?

The force of kinetic friction
stops the block.

fk = ?

Uktable

Uk = .30

fk = Fnuk = Fguk = mguk

= (10. kg)(9.8 m/s2).30

= 29. N

Example 4

A 53. kg block, slowed by friction, has an acceleration of -0.10 m/s2. What is the force of friction on the block?

m = 53. kg     a = -.10 m/s2

fk = F = ma

fk = F = 53. kg(-.10 m/s2)

= -5.3 N

Example 5

A force of 8.0 N gives a 3.0 kg mass an acceleration of 2.0 m/s2 to the right. What is the friction on the block?

Fapplied = 8.0 N Right     m = 3.0 kg     a = 2.0 m/s2 Right

Fnet = ma = 3.0 kg(2.0 m/s2)

= 6.0 N

What friction force will produce a net force of 6.0 N?

friction = 2 N left

Extension: Friction on a Ramp

How does the magnitude of the friction force on a box on a ramp change when the angle of the ramp increases?

Friction decreases because the
normal force decreases

Review - Which law of motion best explains this?

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LiquidNitrogen_pingpong

3rd Law of Motion
Action/Reaction

Review

Friction Video
Georgia Pacific Broadcasting

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