Do Now warm-up prompt

The Big Ideas

Temperature = average kinetic energy of particles. K = °C + 273

Thermal energy = total energy of all the particles (depends on mass too).

Heat (Q) = energy transferred from hot to cold, in joules.

Thermal equilibrium = same temperature, no net heat flow.

Second law: heat flows on its own only from hot to cold; energy spreads out.

Closed system: Qlost = Qgained

Q = mcΔT
SubstanceSpecific Heat, c (J/g•°C)
Water (liquid)4.18
Aluminum0.90
Iron0.45
Copper0.39

Explore

Pick the materials, masses, and starting temperatures, then press “Touch them!”

Mixed Practice

Problem 1

Convert −23 °C to kelvins.

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−23 + 273 = 250 K

Problem 2

Read the graph: which object started hotter, what is the equilibrium temperature, and which object gained energy?

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The hot object (red) started at 90 °C. Equilibrium is 50 °C. The cold object (blue) gained energy.

Temperature versus time graph for review question 2
Problem 3

How much heat is needed to raise 400. g of aluminum from 25 °C to 75 °C?

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Q = (400.)(0.90)(50.) = 18,000 J

Problem 4

A 200.-g iron bolt at 120. °C is dropped into 150. g of water at 20. °C. Find the final temperature.

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mc: iron 90. J/°C, water 627 J/°C  →  Tf = (10,800 + 12,540) / 717 = 32.6 °C

Problem 5

Explain, using particles, why a cold spoon placed in hot cocoa warms up.

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Fast-moving particles in the cocoa collide with the slower particles of the spoon and transfer kinetic energy. The spoon’s particles speed up (its temperature rises) while the cocoa’s slow down, until both reach the same temperature.

Problem 6

A student says, “The ice cube gave its cold to the drink.” Correct the statement.

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Cold does not transfer. Heat (energy) flowed from the warmer drink into the ice, so the drink lost energy and cooled down.

Check Your Understanding

6 quick questions — pick an answer to see if you’re right.

1. Which quantity is measured in joules?

2. Heat will flow between two objects in contact only if they have different

3. How much heat raises 20. g of water by 10. °C?

4. Equal masses of aluminum and water absorb the same heat. Which warms more?

5. A hot block cools from 90 °C as it warms 20 °C water. The final temperature must be

6. Which best describes the second law of thermodynamics?

NYSSLS Regents Practice · Thermal Energy · Systems & Efficiency

A Car Engine’s Cooling System

A gasoline engine transforms the chemical energy in fuel. For every 100. kJ of chemical energy released, about 25 kJ becomes useful mechanical work, and the rest becomes thermal energy. A liquid coolant (mostly water) carries thermal energy from the engine to the radiator, where it is transferred to the air.

How much thermal energy must the cooling system and exhaust remove for every 100. kJ of fuel energy?

▶ Want a challenge? Open 6 more Regents-style questions  (harder · mixed formats)

Challenge score: 0 / 6

Substitute values

C1. In one interval, 5.0 kg (5000 g) of water-based coolant absorbs 75 kJ (75,000 J) of thermal energy. Substitute numerical values into a mathematical representation that can be used to determine the temperature rise of the coolant (c = 4.2 J/g·°C). Then calculate the temperature rise.

ΔT = ( J)( g)( J/g·°C) = °C
Multiple choice

C2. Which sequence correctly shows the main energy transformations in the car?

Determine the value

C3. The engine converts 25% of the fuel’s chemical energy into mechanical work. To deliver 20. kW of mechanical power to the wheels, determine the rate at which the fuel must release chemical energy.

Pfuel = kW
Support or Refute · Justify

C4. A mechanic makes the following claim.

Claim: Pure antifreeze (c = 2.4 J/g·°C) would be a better coolant than water, because 5.0 kg of it would absorb the same 75 kJ with a smaller temperature rise.

Place a check mark in either the Support or Refute box. Justify your response using a mathematical relationship.

Multiple choice

C5. An inventor claims a new engine converts 100% of fuel energy into mechanical work. Which response is best?

Constructed response

C6. An engineer proposes installing a larger radiator in the car. Identify one benefit and one drawback of this design change.