AP Physics 1
Module - Gravity

AP Gravity Title
All Lessons

I. Gravity Worksheet

A. Defined - Gravity is the of between any two objects in the universe.

$$F = \frac{G m_1 m_2}{r^2}$$

$G$ – Universal Gravitational constant $= 6.67 \times 10^{-11} \text{ N}\cdot\text{m}^2/\text{kg}^2$

$m_1$ and $m_2$ – masses of the two attracting objects

r - The distance measured between the of the two objects.

center distance

B. Relationships

State the relationship between Gravitational Force (F) and distance (r): . What is the plot shape for this relationship?

If the distance between two objects is tripled, the gravitational force between them will change by a factor of

State the relationship between Gravitational Force (F) and mass (m): . What is the plot shape for this relationship?

Example 1: Two objects, with masses $m_1$ and $m_2$, are originally a distance r apart. The magnitude of the gravitational force between them is $F$. The masses are changed to $2m_1$ and $2m_2$, and the distance is changed to $4r$. What is the magnitude of the new gravitational force in terms of $F$?

Teacher Workspace: Deriving Ex 1

Module I Teacher Key

Claim: The magnitude of the new gravitational force is $F/4$.
Evidence: Substituting the variables into the formula: $F_{new} = G \frac{(2 m_1)(2 m_2)}{(4 r)^2} = \frac{4 G m_1 m_2}{16 r^2} = \frac{1}{4} \left( \frac{G m_1 m_2}{r^2} \right)$.
Reasoning: According to Newton's Law of Universal Gravitation, force is directly proportional to the product of masses and inversely proportional to the square of the distance. Doubling both masses increases the force by a factor of 4. Increasing the distance by a factor of 4 decreases the force by a factor of $4^2 = 16$. The net effect is $4/16$, resulting in $1/4$ the original force.

Quick Check

3 questions on I. Defined & Relationships — pick an answer to check yourself.

1. If the distance between the centers of two objects is tripled, the gravitational force between them becomes…

2. Two 100 kg spheres have centers 2.0 m apart. What is the gravitational force between them? (G = 6.67 × 10⁻¹¹ N·m²/kg²)

3. Two masses feel gravitational force F. Both masses are doubled and the distance is made 4 times larger. What is the new force?

II. Satellite & Weight

Example 2: Satellite A and Satellite B have the same mass and are orbiting the same planet. If the gravitational force on satellite A is 160,000 N and it is at a distance $R$ from the center, what is the gravitational force on satellite B if it is at a distance of $2R$?

Satellite comparison

Example 3: A rocket weighs 18,000 N at the Earth's surface. If the rocket rises to a height where its total distance from the center of the Earth is 3 Earth radii ($3R_e$), calculate its weight at that new location.

Rocket radii

When an object is on the Earth, the net gravitational force on that object is defined as its weight ($F_g = mg$).

C. Weight – The net gravitational force exerted on an object by a celestial body.

Teacher Workspace: Weight and Radius Analysis

Module II Teacher Key

Claim: The rocket's weight at 3 Earth radii is 2,000 N.
Evidence: $F_g \propto 1/r^2$. The distance from the center of the Earth increases from $1R_e$ to $3R_e$.
Reasoning: Weight is the measure of the gravitational pull between the Earth and the object. Since the distance from the center of mass has tripled, the force of attraction must be divided by the square of the distance change ($3^2 = 9$). Therefore, $18,000 \text{ N} / 9 = 2,000 \text{ N}$.
View from above the North Pole: a satellite 35,800 km up orbits once every 24 hours, the same time Earth takes to spin, so it stays directly above the same spot on the ground NYSSLS Reading Passage icon

NYSSLS Reading Passage · 2D Motion

Physics of Geosynchronous Satellites

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Quick Check

3 questions on II. Satellite & Weight — pick an answer to check yourself.

1. The gravitational force on a satellite at distance R from a planet's center is 160,000 N. What is the force on an identical satellite at 2R?

2. A rocket weighs 18,000 N on Earth's surface. What does it weigh at a distance of 3 Earth radii from Earth's center?

3. An astronaut moves from Earth's surface to 2 Earth radii from Earth's center. What happens to her mass and weight?

III. Surface Gravity

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Variations in Gravity Near the Earth's Surface:

New York - 9.803 m/s² / Denver - 9.796 m/s² / North Pole - 9.832 m/s²

Based on the formula for gravitational acceleration, what physical factor explains the differences in $g$ at these locations?

Richer and Kater measuring Earth's gravity with a pendulum clock

This is exactly how these tiny differences in $g$ were first discovered: in 1672, Jean Richer noticed his pendulum clock ran slow near the equator — the same idea Henry Kater later refined into a precision instrument. Click the image for a larger view.

$$(Weight) \text{ } F_g = mg = \frac{G m m_e}{r^2}$$

Simplify the expression above to find the acceleration due to gravity $g$ on a planet's surface: $g = $

In this formula, $M_e$ represents the of the planet.

Example 4: Mars has a mass approximately 1/10 that of Earth and a diameter approximately 1/2 that of Earth. Based on this data, calculate the acceleration of a falling body near the surface of Mars in terms of $g$.

Giancoli p. 131 #28: A 2100-kg spacecraft is in a circular orbit at a distance of 2.0 Earth radii from the Earth's center. Calculate the magnitude of the force of gravity exerted on the spacecraft by the Earth.

Giancoli 28

Giancoli p. 131 #32: A hypothetical planet has a radius 1.5 times that of Earth, but has exactly the same mass as Earth. What is the value of the acceleration due to gravity on the surface of this hypothetical planet?

Giancoli 32
Teacher Workspace: Deriving Planetary g

Module III Teacher Key

Claim: The surface gravity of Mars is exactly $0.4g$.
Evidence: $g_{mars} = G \frac{(0.1 M_e)}{(0.5 R_e)^2} = \frac{0.1}{0.25} g_{earth} = 0.4 g$.
Reasoning: The acceleration due to gravity on a planet's surface depends on the ratio of the planet's mass to its radius squared. Although Mars has 10 times less mass than Earth, its much smaller radius places the surface significantly closer to its center of mass, which increases the gravitational field strength by a factor of 4. The final result is a surface gravity that is 40% of Earth's value.

Gravitational Field Explorer

Compare surface g on Earth, the Moon, Mars, and Jupiter, then drag the test mass to see g = Gm/r² fall off with distance.

Gravitational Fields Notes

Quick Check

3 questions on III. Surface Gravity — pick an answer to check yourself.

1. A planet has the same mass as Earth but 1.5 times Earth's radius. What is g on its surface? (Earth's g = 9.8 m/s²)

2. Mars has about 1/10 of Earth's mass and 1/2 of Earth's diameter. Its surface gravity is about…

3. g is 9.803 m/s² in New York but only 9.796 m/s² in Denver. What best explains the difference?

IV. Orbital Proofs

Orbital Mechanics Simulator



Rank the gravitational forces from greatest to smallest.

Example 5: Use the principles of circular motion and universal gravitation to prove that the orbital velocity of a satellite is independent of its own mass.

Teacher Workspace: $F_g = F_c$ Derivation

a) From your derivation, identify which two physical quantities determine the orbital velocity $v$ and the orbital period $T$:

b) How does decreasing the orbital radius affect the orbital velocity $v$ and the orbital period $T$ ?

Module IV Teacher Key

Claim: The mass of the orbiting satellite has no effect on the velocity required to maintain a stable circular orbit.
Reasoning: By setting the Gravitational Force equal to the Centripetal Force necessary for circular motion ($G \frac{M m_s}{r^2} = \frac{m_s v^2}{r}$), the mass of the satellite ($m_s$) appears on both sides of the equation and cancels out algebraically. This proves that any object, regardless of its mass, must travel at the same tangential speed to maintain a specific orbital radius around a central body.
Satellites in low, medium, and geosynchronous orbits around Earth, labeled by use: research and weather imaging in LEO, GPS in MEO, TV and communications in GEO, with gravity pulling toward Earth's center NYSSLS Reading Passage icon

NYSSLS Reading Passage · Circular Motion

Eyes You'll Never See: The Many Uses of Artificial Satellites

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Quick Check

3 questions on IV. Orbital Proofs — pick an answer to check yourself.

1. A satellite orbits a planet with GM = 4.0 × 10¹⁴ m³/s² at r = 1.0 × 10⁸ m. What is its orbital speed?

2. Satellite B has twice the mass of satellite A, and both orbit Earth at the same radius. Compared with A, B's orbital speed is…

3. If a satellite moves to a smaller circular orbit, what happens to its orbital speed v and period T?

V. Gravity Questions

Total Score: 0 / 37

VI. Extended Analysis
(Free Response)

1. Lunar Eclipse Net Force: During a total lunar eclipse, the Moon, Earth, and Sun are aligned in a straight line, with the Earth positioned directly between the Moon and the Sun. Use the following data to solve:
Mass of the Moon ($m_m$) = $7.4 \times 10^{22} \text{ kg}$
Mass of the Earth ($M_e$) = $6.0 \times 10^{24} \text{ kg}$
Mass of the Sun ($M_s$) = $2.0 \times 10^{30} \text{ kg}$
Earth-Moon distance ($r_{em}$) = $3.8 \times 10^8 \text{ m}$
Earth-Sun distance ($r_{es}$) = $1.5 \times 10^{11} \text{ m}$

  1. Calculate the magnitude of the gravitational force exerted on the Earth by the Moon.
  2. Calculate the magnitude of the gravitational force exerted on the Earth by the Sun.
  3. Calculate the magnitude and direction of the net gravitational force exerted on the Earth by both the Moon and the Sun during this alignment.
Teacher Workspace: Vector Calculations

2. 2.10-kg brass ball transported to Moon: A solid brass ball is manufactured with a mass of 2.10 kilograms. It is transported to the surface of the Moon.
Radius of the Moon = $1.74 \times 10^6$ meters
Mass of the Moon = $7.35 \times 10^{22}$ kilograms

Same 2.10 kg brass ball on Earth and on the Moon: an equal-arm balance stays level in both places, while a spring scale stretches much less on the Moon
  1. Calculate the acceleration due to gravity on the lunar surface.
  2. Compare the mass of the ball on Earth to its mass on the Moon. Explain any difference.
  3. Calculate the weight of the ball when it is on the surface of the Earth.
  4. Calculate the weight of the ball when it is on the surface of the Moon.
Teacher Workspace: Mass vs Weight Proof

3. Earth Satellite Variable Derivation: A satellite of mass $m$ is placed in a stable circular orbit around the Earth. The Earth has a mass $M_e$ and a radius $R_e$. The satellite orbits at a distance $a$ measured from the center of the Earth. Express all algebraic answers strictly in terms of $a$, $m$, $M_e$, $R_e$, and $G$.

Satellite diagram
  1. Derive the expression for the gravitational force acting on the satellite.
  2. Derive the expression for the centripetal acceleration of the satellite.
  3. Determine if the acceleration of the satellite in this orbit is greater than, less than, or equal to the acceleration $g$ at the surface of the Earth. Justify your answer.
  4. Derive the expression for the tangential orbital velocity of the satellite.
  5. How much work is done by the gravitational force on the satellite during one complete orbit? Justify your answer.
  6. Derive the expression for the orbital period $T$ of the satellite.
Teacher Workspace: Algebraic Derivations

Module VI Teacher Key

Claim (Work): The work done by gravity on a satellite in a circular orbit is exactly zero Joules.
Evidence: Work is defined by the dot product $W = F \cdot d \cdot \cos\theta$. In a circular orbit, the gravitational force $F_g$ is always directed radially toward the center, while the displacement $d$ is always tangential to the path, meaning the angle $\theta = 90^\circ$.
Reasoning: Work is only performed when there is a component of force acting in the direction of the object's displacement. Since gravity acts perpendicularly to the satellite's motion at every point in a circular orbit, no energy is transferred to or from the satellite's kinetic energy. Gravity serves only to change the direction of the velocity, not its magnitude.

Quick Check

3 questions on VI. Extended Analysis — pick an answer to check yourself.

1. A satellite moves in a circular orbit. How much work does gravity do on it during one complete orbit?

2. A 2.10 kg brass ball is taken to the Moon, where g ≈ 1.6 m/s². What is its weight there?

3. A satellite orbits at distance a from Earth's center, where a is greater than Earth's radius Re. How does its acceleration compare with g at Earth's surface?

VII. Case Studies

4. Jupiter Satellite: A research satellite is in a stable circular orbit around Jupiter at a radius $R$. Jupiter has a mass $M_J = 1.90 \times 10^{27} \text{ kg}$ and a mean radius $R_J = 7.14 \times 10^7 \text{ m}$.

  1. Starting from first principles ($F_g = F_c$), derive an expression for the orbital velocity of the satellite at a radius $R$ from Jupiter's center.
  2. If the satellite were moved to a higher orbit with a larger radius, describe how its orbital velocity would change. Provide a physical explanation.
  3. Derive an expression for the orbital period $T$ of the satellite.
  4. Calculate the required orbital radius $R$ for a satellite that must have a period of exactly $3.55 \times 10^4 \text{ s}$.
Teacher Workspace: Jupiter Orbital Analysis

5. Sojourner Rover Case Study: The Pathfinder spacecraft successfully landed on the Martian surface on July 4, 1997. It deployed a small rover named Sojourner to explore the landing site. Use the planetary and rover data provided below to complete the following analysis.

Mars Planetary Data: Radius = $0.53 R_e$, Mass = $0.11 M_e$.
Sojourner Rover Data:
Mass = $11.5 \text{ kg}$
Wheel diameter = $0.13 \text{ m}$
Stored Energy in Battery = $5.4 \times 10^5 \text{ J}$
Power consumption for driving = $10 \text{ W}$
Constant driving speed = $6.7 \times 10^{-3} \text{ m/s}$

  1. Calculate the acceleration due to gravity at the surface of Mars expressed as a fraction of $g$ (Earth's surface gravity).
  2. Calculate the weight of the Sojourner rover when it is on the surface of Mars.
  3. To leave the lander, Sojourner must roll down a ramp inclined at 20° to the horizontal. Calculate the minimum normal force the ramp must provide to support the rover.
  4. What is the magnitude of the net force acting on Sojourner as it travels across a level Martian surface at a constant velocity? Justify your answer.
  5. Calculate the maximum total distance Sojourner can travel on a horizontal surface using only its stored battery energy.
  6. If 0.010% of the driving power is used to overcome atmospheric drag on Mars, calculate the magnitude of the drag force acting on the rover.
Teacher Workspace: Sojourner Detailed Proofs

Module VII Teacher Key

Claim (Sojourner Net Force): The net force acting on the rover is exactly zero Newtons.
Reasoning: According to Newton's First Law of Motion, any object traveling at a constant velocity is in a state of dynamic equilibrium. This implies that the sum of all forces acting on the rover—including the driving force, friction, and atmospheric drag—must perfectly balance out, resulting in zero net acceleration and therefore zero net force.
Claim (Range): Based on the provided energy and power data, Sojourner can travel approximately 362 meters before exhausting its battery.
Newton's law of universal gravitation beside Einstein's curved spacetime NYSSLS Reading Passage icon

NYSSLS Reading Passage · Dynamics

The Law That Can't Explain Itself: Gravity and the Biggest Myth in Science

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Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. Two masses m₁ and m₂ attract with force F at distance r. Both masses are doubled and the distance is changed to 4r. What is the new force?

2. A rocket weighs 18,000 N at Earth's surface. What is its weight at 3 Earth radii from Earth's center?

3. Mars has about 1/10 Earth's mass and 1/2 Earth's diameter. What is the gravitational acceleration at Mars's surface in terms of g?

4. For a satellite in a circular orbit, which quantities determine its orbital speed?

5. How much work does gravity do on a satellite during one complete circular orbit?

What, If Anything, Is Wrong?No calculator
Farther From Earth

A satellite feels a gravitational force F when it is a distance r from Earth's center. A student predicts the force at 2r and 3r:

Earth r2r3r FF/2 ?F/3 ? distances measured from Earth's center

Student: "Gravity gets weaker as you move away, so at twice the distance the force is half, F/2. At three times the distance it's one-third, F/3."

What, if anything, is wrong? If something is wrong, explain the error and fix it. If nothing is wrong, explain why it is correct.

More Gravity Concept Challenges →

More practice: Gravity QuizMaster
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