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| Onsite Version |
Coulombs Law Notes
Fill In The Blank Notes
F) Coulomb's Law for two fixed point charges
r = distance between charges
|
F = (N) |
kq1 q2 |
| r2 |
F - mutual force of attraction
or repulsion
q - charge of each object
k - electrostatic constant -
8.99 x 109
Nm2/C2
(p. 1 Reference)
AP Physics
AP Physics
Giancoli p. 465) 12
12.
Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C
Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C
r = .50 meters
q1 = 4.0 x 10-8 C
q2 = 6.0 x 10-5 C
k = 8.99 x 109 Nm2/C2
(p. 1 Reference)
|
F = (N) |
k | q1 | q2 |
| r2 | |||
| Scientific Notation/TI83Plus |
| F = | (8.99 x 109 Nm2/C2) | (4.0 x 10-8 C) | 6.0 x 10-5 C |
| (.50 m2) | |||
F = 8.6 x 10–2 Newtons
Relationships
|
F = (N) |
k | q1 | q2 |
| r2 | |||
F,r
Inverse Square
Relationship between
F and r?
How would doubling the distance between the charges change the force between them?
F would be 1/4 as great
F,q?
|
F = (N) |
k | q1 | q2 |
| r2 | |||
Direct
Two charges attract each other with a force of F. If one charged was doubled and the other charge was tripled, how would that change the attractive force between these charges?
|
F = (N) |
k | q1 | q2 |
| r2 | |||
Force increases 6 times
Charged
Water Drop
Orbits a Knitting Needle
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