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Two bodies connected by one string move as one mass, with one shared acceleration — a block on a table, a mass hanging over a pulley, and one rope tying their motion together.

Find a for This System

Play with the simulation, then work through the derivation below

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Free body diagram of a block on a table connected over a pulley to a hanging mass
Two bodies move as one mass w/ one accel.

Newton's Second Law for the System

Free body diagram of the pulley-table system

ΣFnet = ma

Let's make clockwise +

Mg = (m + M)a

The 2 masses get their accel. from hanging mass.

Applies only for frictionless surface.

a = Mg / (M + m)

What If the Roles Were Reversed?

What would the accel. be if the little mass was hanging?

↓

a = mg / (M + m)

What Is the Tension Force of the Rope?

What is the tension force of rope?

↓

ΣFx = ma

Tf = ma

Rule — One Rope, One Tension

Free body diagram used to find the rope tension
Let's make clockwise +

Tension in Terms of M

Free body diagram of the hanging mass M

ΣFy = Ma

Mg − Tf = Ma

Mg − Ma = Tf

Tf = M(g − a)

If Box on Table Had Friction

Free body diagram of the block on the table

coefficient of friction = μ

Free body diagram of the block on the table with friction