Rotational Equilibrium
Ex)
Mass Safe = 15,000 kg
Mass Beam = 1500 kg
Find FA (force of left leg on table)
FB (force of right leg on table)
Using Left leg as pivot point,
St
= 0
Draw all the torques
St
= 0
Torque CW = Torque CCW
10.0m(15,000N) + 15.0m(150,000N)= 20mFB
FB = 120,000 N
SFy = 0
0 = -15,000N - 150,000N + 120,000N + FA
FA = 45,000 N
Giancoli - p. 247) 2, 4, 6
t
Circle
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