AP Energy Notes

The Capacity to Do Work

Energy Unit Intro
All Lessons

I. Energy & Work

Energy Notes - Instructional Video
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A radiometer shows that light is energy by converting light energy into heat energy and then into movement (kinetic energy)

I. Energy – - Vector? Scalar?

II. Work

A. Defined –

Challenge Question: Two people exert a 10 Newton force on a block for 2 meters. One person exerts her force at a 50-degree angle. (frictionless)

Angular Work Comparison

B. Equation:

$\theta$ - the angle between the and

C. Positive and Negative Work

Work is negative when

Work is positive when

Work is 0 when

Examples of negative work

Ex) A 5.0 N force pushes a box 3.0 m North and then 4.0 m east. Find the work done.

Teacher CER Key: Module 1
Evidence: Energy is the capacity to do work. Work ($W$) is the transfer of energy ($W$ $= Fd\cos\theta$).
Claim: Energy and Work are Scalar quantities measured in Joules ($J$).
Reasoning: Scalar quantities have magnitude but no direction. In the North/East example: $W_{total}$ $= (5.0 \, N)(3.0 \, m) + (5.0 \, N)(4.0 \, m)$ $= 15.0 \, J + 20.0 \, J$ $= 35.0 \, J$.

Quick Check

3 questions on I. Energy & Work — pick an answer to check yourself.

1. A 10 N force pulls a box 4.0 m along the floor; the force is at 60° to the displacement. How much work does it do?

2. A waiter carries a tray horizontally across a room at constant velocity. How much work does his upward force on the tray do?

3. A 5.0 N force pushes a box 3.0 m north, then 4.0 m east, always in the direction of motion. Total work done?

II. Work Case Studies

W = Fd

Video Instruction

Ex 1) Object pushed at an angle, f≠0, Mass m, Force F, μ, Fn

Find the Net Work done on the mower in terms of the variables given

Lawnmower Analysis

Ex 2) Find the minimum work needed to push a 950 kg car 810 m up a 9.0 deg incline,

W ork is minimal when

Incline Car

a) no friction

b) friction μk = 0.25

Ex 3) Textbook p. 162) 8

Instructional Video

330 kg piano, slides down 3.6 m, 28° incline / uk = .40. Man prevents the piano from accelerating down the incline

Piano Incline

(a) Force exerted by the man?

b) Work done by a man on the piano?

c) Work done by friction?

d) Work done by the force of gravity?

(e) Net work done on the piano?


D. Finding Work using a F vs. d plot

Instructional Video

Ex 4)

F vs d plot

W =

Ex 5) p. 162) 14 a) Sketch the plot described below

Force Plot

b) Find the work

Teacher CER Key: Module 2
Ex 2 Claim: $W_{min}$ $= 1.18 \times 10^6 \, J$. $W_{friction}$ $= 1.86 \times 10^6 \, J$.
Ex 2 Reasoning: $W$ $= mgh$ $= (950.0 \, kg)(9.8 \, m/s^2)(810.0 \, m \sin 9.0^\circ)$ $= 1,179,577.0 \, J$. With friction: $W$ $= \Delta PE + f_k d$ $= 1.18 \, MJ + \mu (mg\cos\theta)d$ $= 1.86 \, MJ$.
Ex 4 Claim: $Work$ $= 15.0 \, J$.
Ex 4 Reasoning: Area of the triangle under the $F$ vs $d$ curve: $0.5 \cdot Base \cdot Height$ $= 0.5 \cdot (6.0 \, m) \cdot (5.0 \, N)$ $= 15.0 \, J$.

Quick Check

3 questions on II. Work Case Studies — pick an answer to check yourself.

1. On a force vs. displacement graph, the force rises steadily from 0 N to 5.0 N over 6.0 m. How much work is done?

2. What is the minimum work needed to push a 100 kg cart up a 5.0 m frictionless ramp to a height of 2.0 m? (g = 9.8 m/s²)

3. A man holds back a piano so it slides down a ramp at constant velocity. What is the net work done on the piano?

III. Potential Energy

Potential Energy / Work - Video Instruction

Potential Energy – Stored energy due to or

Gravitational PE

Equation - or

W = ΔPE = mgh

W is + when

W is - when

Ex 1) A 1.60 m person lifts a 2.10 kg book from the ground to 2.20 m above the ground. a) How much work was done lifting the book?

Elastic PE

Equation: PE = Fx     F – Average Force     x – stretch/compression

Ideal Spring – F and stretch

Spring

Spring Constant k = F/x

Hooke's Law: a spring stretches 0, 1, and 2 units under forces of 0, W, and 2W

Ex 2) A spring with k = 53 N/m hangs vertically on a ruler. The end of the spring is next to the 15 cm mark on the ruler. If a 2.5 kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks?

PE = [F/2]x = 1/2kx2

Ex) Plot of PE vs x?

Elastic P.E./Plot

PE = of the triangle under F vs x graph

Ex 3) Find the Elastic PE when the spring is stretched 6 m

PE graph

Ex 4) If 15. Joules of energy are stored in the stretched spring, what is the value of the spring constant?

Unstretched spring 0.50 m long; the same spring stretched to 1.00 m by a hanging weight

Ex 5) A 1200 kg car rolling on a horizontal surface has a v = 65 km/hr when it strikes a horizontal coiled spring and is brought to rest at a distance of 2.2 m. What is the spring constant of the spring?

Teacher CER Key: Module 3
Ex 1 Claim: $Work$ $= 45.3 \, J$.
Ex 1 Reasoning: $W$ $= mgh$ $= (2.10 \, kg)(9.8 \, m/s^2)(2.20 \, m)$ $= 45.3 \, J$.
Ex 4 Claim: $k$ $= 30.0 \, N/m$.
Ex 4 Reasoning: $PE_s$ $= 0.5kx^2$ $\implies 15.0 \, J$ $= 0.5 \cdot k \cdot (1.0 \, m)^2$ $\implies k$ $= 30.0 \, N/m$.

Quick Check

3 questions on III. Potential Energy — pick an answer to check yourself.

1. How much work is done lifting a 2.0 kg book 1.5 m straight up at constant speed? (g = 9.8 m/s²)

2. An ideal spring's stretch is doubled. Its stored elastic potential energy…

3. A spring stores 15 J when stretched 1.0 m from its natural length. What is its spring constant?

IV. Kinetic Energy
& Power

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Kinetic Energy / Power - Video Instruction

I. Kinetic Energy

I. Kinetic Energy – Energy of

A. KE = Work to stop or Work to get an object from rest to a certain speed

Derive KE Equation

KE = W = Fd Where Vf = 0

KE = (ma)d

Equation -

B. KE/m relationship     KE/v relationship

Plot shape

C. When Work is done on an object KE is changed:

W = ΔKE

When is the Work done on an object Negative?

When is the Work done on an object Positive?

D. Scalar or Vector?

Ex 1) A softball having a mass of .25 kg is pitched at 95 km/hr. When it reaches the plate, the ball slows down by 10%. Neglecting gravity, estimate the average force of friction if the distance to the plate = 15 m

Ex 2) baseball (m = 140 g) traveling 32 m/s caught by a glove and moving the glove back 25 cm. Average F of the ball on the glove?


Power

Power - Video Instruction

II. Power - the rate of doing or expending

A. Equation P = W/t = =

B. Scalar or Vector?

C. Units

Ex 3) 1440 kg car accelerates from rest to 95 km/hr in 7.4 sec. What average power is used?

Ex 4) A 95 kg football player runs upstairs in 66 s. The stairs are 140 m long at an angle of 32° (constant V)

Her power output vertically is

Ex 5) 1200 kg car has a max. power output of 120 hp. How steep a hill can it climb at a constant speed of 75 km/hr if the frictional force is 650 N?

1 HorsePower = 746 Watts

Teacher CER Key: Module 4
Ex 2 Claim: $Force$ $= 286.7 \, N$.
Ex 2 Reasoning: $W$ $= \Delta KE$ $\implies Fd$ $= 0.5mv^2$ $\implies F(0.25 \, m)$ $= 0.5(0.140 \, kg)(32.0 \, m/s)^2$ $= 71.68 \, J$ $\implies F$ $= 286.7 \, N$.
Ex 4 Claim: $Power$ $= 1047.8 \, Watts$.
Ex 4 Reasoning: $P$ $= mgh/t$ $= (95.0 \, kg)(9.8 \, m/s^2)$ $(140.0 \, m \sin 32.0^\circ) / 66.0 \, s$ $= 1047.8 \, W$.
Ex 5 Claim: $Angle$ $= 10.5^\circ$.
Ex 5 Reasoning: $120 \, hp$ $= 89,520 \, W$. $v$ $= 75 \, km/hr$ $= 20.83 \, m/s$. $P$ $= F_{total} \cdot v$ $\implies F_{total}$ $= 89520 / 20.83$ $= 4297.6 \, N$. This total force overcomes gravity and friction: $F_{total}$ $= mg\sin\theta + f_k$ $\implies 4297.6$ $= (1200)(9.8)\sin\theta + 650$ $\implies \sin\theta$ $= 0.3101$ $\implies \theta$ $= 18.06^\circ$.

Quick Check

3 questions on IV. Kinetic Energy & Power — pick an answer to check yourself.

1. If an object's speed doubles, its kinetic energy…

2. A 50. kg student climbs stairs, rising 4.0 m vertically in 5.0 s at constant speed. What is her average power? (g = 9.8 m/s²)

3. A glove catches a baseball and brings it to rest. The work done by the glove on the ball is…

V. Conservation
of Energy

pdf Resource Review - Instructional Video
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I. Law of Conservation of Energy - unless is done on or by a system, its total mechanical energy does not change.

Ex 1) Fill in the missing energies

Ignore friction

Rollercoaster energies

Ex 2) a) If friction is negligible when the RED ball is released, how high will it rise?

A   B   C   D   Cannot be determined

b) If friction is negligible when the BLUE ball is released, how high will it rise?

A   B   C   D   Cannot be determined

If KE at A is 0 J, find the KE and PE at each point (frictionless)

Track points map

Ex 3) Fill out the chart below

KEPE
A0
B
C
D
E
F
G

Ex 4) What physics law explains why the cart will not reach point H and I?

Ex 5) If PE at A = 10. J, KE = 0, and PE at C = 3.0 J, find the PE and KE at all other points

Hill energy plot
Ballistic pendulum diagram

A ballistic pendulum, like the one Benjamin Robins used in the 1740s, applies this same collision-then-oscillation idea to measure projectile speed. Click the image for a larger view.

Ex 6) 1.0 kg pendulum swings to a height of .20 m above its lowest point. K.E. of the pendulum at the lowest point?

Pendulum Diagram

Ex 7) 5.00-kg cart at the foot of a hill 10.0 m high. For the cart to reach the top of the hill, what is the minimum KE of the cart in the position shown?

Hill cart

Ex 8) Find the height of the pendulum in terms of θ and L (pendulum length)

Pendulum geometry schematic
Teacher CER Key: Module 5
Ex 1 Claim: $TME$ $= 100.0 \, J$ at all points.
Ex 1 Reasoning: $\Sigma E$ $= PE + KE$. Frictionless systems conserve mechanical energy. If $PE$ $= 100.0 \, J$ and $KE$ $= 0.0 \, J$ at start, total is always $100.0 \, J$.
Ex 7 Claim: $KE_{min}$ $= 490.0 \, J$.
Ex 7 Reasoning: $KE_{start}$ $= PE_{peak}$ $= mgh$ $= (5.00 \, kg)(9.8 \, m/s^2)(10.0 \, m)$ $= 490.0 \, J$.

Quick Check

3 questions on V. Conservation of Energy — pick an answer to check yourself.

1. A 1.0 kg pendulum swings up to 0.20 m above its lowest point. What is its kinetic energy at the lowest point? (g = 9.8 m/s²)

2. A frictionless coaster starts from rest with 100 J of potential energy. At a lower point its PE is 40 J. What is its KE there?

3. A ball is released from rest at height h on a frictionless U-shaped track. How high will it rise on the other side?

VI. Advanced COE
& Work

pdf Resource Instructional Video
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Relationship: $W = \Delta KE + \Delta PE + W_f$

Energy Problems

1. Neglecting air resistance, how high will a 0.325-kilogram rock go if thrown straight up by someone who does 115 J of work on it?

2. A hammerhead with a mass of 2.0 kilogram is allowed to fall onto a nail from a height of 0.40 meters. What is the maximum amount of work it could do on the nail?

3. A 1,200-kilogram car traveling at 110 kilometers per hour (30.55 m/s) comes to a stop.

a. How much work (negative) was done on the car? Don't solve, just show the equation.

b. Where does the car's kinetic energy go?

4. A baseball (m = 0.140 kilograms) traveling 35 meters per second moves a fielder's glove backward 0.25 meters when the ball is caught and brought to rest. What is the average force exerted by the ball on the glove?

5. In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy. With what minimum speed must the athlete leave the ground to lift her center of mass 2.10 meters across the bar at 0.70 meters per second?

Conservation of Energy Problems
Video Instruction

1.

Roller coaster problem diagram

a. A 5.0-kg block starts at a speed of 10. m/s at the top of a "roller-coaster," as shown above. What is its KE at the top?

b. What is its GPE at the top (relative to the ground)?

c. What is the block's total energy at the top?

2. If the track is entirely frictionless and there is no air resistance, the block will not lose any energy until it reaches the level surface where μ=0.5 and the frictional force "takes away" energy.

a. Find the GPE at point A and then calculate how much of the block's total energy must be in the form of KE. Also, find the speed at point A.

b. Repeat the above for points B, C, and D.

3. After the block exits the loop-the-loop, it encounters a horizontal, rough surface (μ = 0.5) and comes to a stop.

a. How much total energy does the block have just as it exits the loop-the-loop?

b. How much energy does the frictional force "take away" in bringing the block to a stop?

c. How large is the frictional force acting on the block?

d. How far does the block slide before coming to a stop?

Conservation of Energy Problems with Work
Instructional Video (1 - 2)

1. A 20. kg block, originally at rest, is pulled across a rough surface (μ = 0.10) by a 100. N force angled at 36.87° for 20. m. Find the work done by each of the following forces.

μ = 0.10 20. kg P = 100. N 36.87°

a. Find the work done by the force of friction

b. Find the work done by Force 100. N.

c. Find the total work done by all of the above forces.

d. Find the speed of the block the instant it is 20. meters to the right of its starting position.

2. A 20.-kg block slides across a frictionless floor and then slides up 10. meter along a rough 36.87° incline (μ =0.20) until it comes to a brief stop. What is the initial speed of the block prior to sliding up the incline?

A 20 kg crate slides with unknown speed v across a frictionless floor, then 10 m up a rough 36.87 degree incline (mu = 0.20) to a stop at unknown height h

3. A 5.0 kg box is pulled up a rough (μ = 0.10) incline by a force of 50. N for a distance of 20. m. If the speed of the box is 5.0 m/s initially, what is its speed the instant it has traveled the 20. -m up the incline?

Equation

Incline work

4. A 10.-kg box is released from rest and slides down an 800. cm tall incline and then compresses a spring (k = 50. N/m). What is the maximum spring compression before the box is pushed away?

Note: all surfaces are frictionless except the crosshatched surface where d = 10. m and has a coefficient of friction of 0.10.

Box of mass m at point A on a hill of height H slides down, crosses a rough patch of length d, and compresses a spring of constant k against a wall

5. A 10.-kg box is held against a spring, which is compressed 2.0 m as shown. If the box is moving at 10. m/s when it reaches the top of the incline, what is the spring constant (k)?

Note: all surfaces are frictionless, and the height (H) of the incline is 6.0 meters.

Compressed spring
Atwood System Diagram

6. The system above is released from rest. The instance the suspended mass has fallen 8.0 meters, the blocks have speeds of 8.0 m/s. ($m_{susp} = 6.0 \, kg$, $m_{table} = 4.0 \, kg$).

a. How much GPE did the suspended mass "lose" the instant the suspended mass has fallen 8 meters?

b. Where did the GPE "lost" go? Note: disregard air resistance

c. What is the KE of each block, the instant the suspended mass has fallen 8 meters?

d. How much energy did the frictional force "take away" from the system (neg. work)?

e. How large is the frictional force?

f. What is the coefficient of friction?

Teacher CER Key: Module 6
Energy Prob 1 Claim: Height $= 36.1 \, m$.
Energy Prob 1 Reasoning: $W$ $= mgh$ $\implies 115.0 \, J$ $= (0.325 \, kg)(9.8 \, m/s^2)h$ $\implies h$ $= 36.1 \, m$.
COE Prob 1c Claim: $E_{total}$ $= 1230.0 \, J$.
COE Prob 1c Reasoning: $KE$ $= 0.5(5.0 \, kg)(10.0 \, m/s)^2$ $= 250.0 \, J$. $PE$ $= (5.0 \, kg)(9.8 \, m/s^2)(20.0 \, m)$ $= 980.0 \, J$. $Total$ $= 1230.0 \, J$.
Work Prob 1 Claim: $v$ $= 11.5 \, m/s$.
Work Prob 1 Reasoning: $F_{net}$ $= 100.0\cos(36.87^\circ)$ $- 0.1(mg - 100.0\sin(36.87^\circ))$ $= 66.4 \, N$. $W_{net}$ $= 66.4 \, N \cdot 20.0 \, m$ $= 1328.0 \, J$. $1328.0 \, J$ $= 0.5(20.0 \, kg)v^2$ $\implies v$ $= 11.5 \, m/s$.
Work Prob 6 Claim: $W_f$ $= 336.0 \, J$.
Work Prob 6 Reasoning: $PE_{lost}$ $= (10.0 \, kg)(9.8 \, m/s^2)(8.0 \, m)$ $= 784.0 \, J$. $KE_{gained}$ $= 0.5(10.0+4.0 \, kg)(8.0 \, m/s)^2$ $= 448.0 \, J$. Friction energy loss $= 784.0 \, J - 448.0 \, J$ $= 336.0 \, J$.
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Check Your Understanding

5 quick questions — pick an answer to see if you’re right.

1. A 5.0 N force pushes a box 3.0 m north, then 4.0 m east, always in the direction of motion. How much total work is done?

2. In W = Fd cos θ, when does a force do zero work on a moving object?

3. A spring stores 15 J of elastic potential energy when stretched 1.0 m. What is its spring constant?

4. A 0.20 kg ball moving at 10 m/s is caught, pushing the glove back 0.10 m. What average force does the ball exert on the glove?

5. A car's speed doubles. What happens to its kinetic energy?

What, If Anything, Is Wrong?No calculator
Will the Car Make It Over the Hill?

A roller-coaster car is released from rest at point A, 30 m above the ground. The track is frictionless. It dips to ground level at B, then climbs toward the top of hill C, which is 35 m high.

ABC 30 m35 m released from rest

Student: "The car will make it over hill C. It builds up a lot of speed going down to B, and all that speed carries it up and over C. At B, all of the potential energy it had at A has turned into kinetic energy."

What, if anything, is wrong? If something is wrong, explain the error and fix it. If nothing is wrong, explain why it is correct.

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