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F) Coulomb's Law for two fixed point charges

 

r = distance between charges

F =
(N)
kq1 q2
r2

F -  mutual force of attraction or repulsion

q - charge of each object

k - electrostatic constant -

8.99 x 109 Nm2/C2
(p. 1 Reference)

 

 

 

AP Physics

 

 

 

 

 

AP Physics

Giancoli p. 465) 12

12.

 

 

 

Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C

 

 

Ex) What is the electrical force between 2 very small objects located .50 m apart when the charge on one object is 4.0 x 10-8 C and the charge on the second object is 6.0 x 10-5 C

 

r = .50 meters

q1 = 4.0 x 10-8 C

q2 = 6.0 x 10-5 C

k = 8.99 x 109 Nm2/C2
(p. 1 Reference)

 

F =
(N)
k q1 q2
r2

 

 

 

 

Scientific Notation/TI83Plus

More

 

F = (8.99 x 109 Nm2/C2) (4.0 x 10-8 C) 6.0 x 10-5 C
(.50 m2)

 

 

F = 8.6 x 10–2 Newtons

 

 

 

Relationships

F =
(N)
k q1 q2
r2

F,r

 

Inverse Square

 

 

Relationship between

F and r?

 

 

 

 

 

 

 

 

 

How would doubling the distance between the charges change the force between them?

 

 

F would be 1/4 as great

 

 

 

 

 

 F,q?

 

 


F =
(N)
k q1 q2
r2

 

 

Direct

 


 

Two charges attract each other with a force of F.  If one charged was doubled and the other charge was tripled, how would that change the attractive force between these charges?

 

 

F =
(N)
k q1 q2
r2

 

 

Force increases 6 times

 

 

 

Charged Water Drop
 Orbits a Knitting Needle

 

 

 

 

Electric Field

 

 

 

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