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Assuming a frictionless, massless pulley, ...

... determine the a of the block after the large block is released

Let's make clockwise positive
Fnet = ma
 
[Mg - mg] = (M + m)a
 
 

Accel of 2 mass
comes from
Weight difference

g(M - m) = a
(m + M)

Only applies when surface frictionless

 
 
Force of tension of the rope
on mass m, M?
Rule - One Rope, 
One Tension
Let's Make Clockwise Positive
 
 
 
ΣFy = Ma
 
Mg - Tf = Ma
 
Tf  = Mg - Ma
 

Pulley / Table

 

 

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